2x^2-10=19x

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Solution for 2x^2-10=19x equation:


Simplifying
2x2 + -10 = 19x

Reorder the terms:
-10 + 2x2 = 19x

Solving
-10 + 2x2 = 19x

Solving for variable 'x'.

Reorder the terms:
-10 + -19x + 2x2 = 19x + -19x

Combine like terms: 19x + -19x = 0
-10 + -19x + 2x2 = 0

Factor a trinomial.
(-1 + -2x)(10 + -1x) = 0

Subproblem 1

Set the factor '(-1 + -2x)' equal to zero and attempt to solve: Simplifying -1 + -2x = 0 Solving -1 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -2x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -2x = 0 + 1 -2x = 0 + 1 Combine like terms: 0 + 1 = 1 -2x = 1 Divide each side by '-2'. x = -0.5 Simplifying x = -0.5

Subproblem 2

Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10

Solution

x = {-0.5, 10}

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